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IMDB rating: 9.40 Plot: Actress-turned-director Lori Petty makes her feature directorial debut with this period drama set in 1976 and exploring a typical day in the life of a decidedly atypical teen named Agnes. Some folks have the luxury of living each day to the fullest, but for Agnes every day is a grueling struggle for survival; her mother is strung-out on drugs, her home has been overrun by degenerates, and her only father figure is a pimp. For Agnes and her two younger sisters this particular day will be marked by both tragedy and triumph, but which will resonate most in the days and weeks to follow? Selma Blair, Bookeem Woodbine, and David Allan Grier star. |
Actors: Bicicchi Joey,Brawner Anthony,Brown Hashim,Christian Jeff,Gerdisch Matthew,Gerdisch Robert,Grier David Alan,Gudahl Kevin,Jones II James Earl,Komenich Rich,Kramer Robert,Legat Jonathan C.,Masud Kazemde Fela,McEwen Adam,McEwen Justin,Drama,
What are the probabilities of these card situations? (I give points!)?
The answers are in the back of the book, but I do not understand the steps to get there. I understand part a, but not the rest for the following problem:
A poker hand is defined as drawing five cards at random without replacement from a deck of 52 playing cards. Find the probability of the following power hands:
a) Four of a kind (four cards of equal face value and one of a different value). Ans=.000024
b) Full house (one pair and one triple cars with equal face value). Ans=.00144
c) Three of a kind (three equal face values plus two cards of different values). =.02113
d) Two pairs (two pairs of equal face value plus one card of different value).= .04754
e) One pair (one pair of equal face value plus three cards of different values). =.42257
a) (13*48)/(52n5)
The rest I am stumped. Please show me the steps. Thanks!
b) 13 ways to choose the rank for the pair, 4C2 = 6 ways to choose the pair. 12 ways to choose the rank of the 3-of-a-kind, 4C3 = 4 ways to choose the three cards. Multiply: 13 * 6 * 12 * 4 = 3744. Divide by 52C5 to get 0.00144
c) 13 ways to choose the rank, 4 ways to choose the three cards. The remaining 2 cards must be different ranks or we have a full house, so choose any two ranks in 12C2 ways. In each rank, choose a card in 4 ways. Total is 13 * 4 * 12C2 * 4 * 4 = 54912.
d) Choose 2 ranks in 13C2 ways. Choose a pair in each rank in 4C2 = 6 ways. Choose the remaining card in 44 ways.
e) Choose the rank in 13 ways, the pair in 4C2 ways. Choose 3 other ranks in 12C3 ways, and the cards in each rank in 4 ways.
| Jan 27, 2010
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